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authorJannis Leidel2009-10-12 14:01:21 +0200
committerMax Howell2009-10-12 18:11:03 +0100
commit2d67ddad2e0d8c87af1ae637919986655341dd87 (patch)
tree9c80b41fce72c53047c438c42f3db53bd72834fc /Library/Formula/python.rb
parentc0bd6611dec15a3a63ca58f034adc29c9479c878 (diff)
downloadhomebrew-2d67ddad2e0d8c87af1ae637919986655341dd87.tar.bz2
Make framework install of Python actually usable.
No offense but the use of --with-framework-name option is totally wrong in the Formula. As noted in the Mac build [notes][1] --with-framework-name is *not* to pass the SDK path, but to rename it (e.g. "AwesomePython.framework" instead of just "Python.framework"). To build it as a Mac OS X framework you need to use the --enable-framework flag instead. The same with the other option -- to build Python universally. The flag --enable-universalsdk is missing. [1]: http://svn.python.org/projects/python/branches/release26-maint/Mac/README
Diffstat (limited to 'Library/Formula/python.rb')
-rw-r--r--Library/Formula/python.rb4
1 files changed, 2 insertions, 2 deletions
diff --git a/Library/Formula/python.rb b/Library/Formula/python.rb
index da0581975..8b5e6afcf 100644
--- a/Library/Formula/python.rb
+++ b/Library/Formula/python.rb
@@ -24,11 +24,11 @@ class Python <Formula
args = ["--prefix=#{prefix}"]
if ARGV.include? '--framework'
- args << "--with-framework-name=/Developer/SDKs/MacOSX#{MACOS_VERSION}.sdk"
+ args << "--enable-framework"
end
if ARGV.include? '--intel'
- args << "--with-universal-archs=intel"
+ args << "--with-universal-archs=intel --enable-universalsdk=/"
end
system "./configure", *args