1 files changed, 383 insertions, 0 deletions
diff --git a/pcp/intl/plural.y b/pcp/intl/plural.y
new file mode 100644
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+++ b/pcp/intl/plural.y
@@ -0,0 +1,383 @@
+%{
+/* Expression parsing for plural form selection.
+   Copyright (C) 2000-2001, 2003, 2005-2006 Free Software Foundation, Inc.
+   Written by Ulrich Drepper <drepper@cygnus.com>, 2000.
+
+   This program is free software: you can redistribute it and/or modify
+   it under the terms of the GNU Lesser General Public License as published by
+   the Free Software Foundation; either version 2.1 of the License, or
+   (at your option) any later version.
+
+   This program is distributed in the hope that it will be useful,
+   but WITHOUT ANY WARRANTY; without even the implied warranty of
+   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
+   GNU Lesser General Public License for more details.
+
+   You should have received a copy of the GNU Lesser General Public License
+   along with this program.  If not, see <http://www.gnu.org/licenses/>.  */
+
+/* For bison < 2.0, the bison generated parser uses alloca.  AIX 3 forces us
+   to put this declaration at the beginning of the file.  The declaration in
+   bison's skeleton file comes too late.  This must come before <config.h>
+   because <config.h> may include arbitrary system headers.
+   This can go away once the AM_INTL_SUBDIR macro requires bison >= 2.0.  */
+#if defined _AIX && !defined __GNUC__
+ #pragma alloca
+#endif
+
+#ifdef HAVE_CONFIG_H
+# include <config.h>
+#endif
+
+#include <stddef.h>
+#include <stdlib.h>
+#include <string.h>
+#include "plural-exp.h"
+
+/* The main function generated by the parser is called __gettextparse,
+   but we want it to be called PLURAL_PARSE.  */
+#ifndef _LIBC
+# define __gettextparse PLURAL_PARSE
+#endif
+
+#define YYLEX_PARAM	&((struct parse_args *) arg)->cp
+#define YYPARSE_PARAM	arg
+%}
+%pure_parser
+%expect 7
+
+%union {
+  unsigned long int num;
+  enum expression_operator op;
+  struct expression *exp;
+}
+
+%{
+/* Prototypes for local functions.  */
+static int yylex (YYSTYPE *lval, const char **pexp);
+static void yyerror (const char *str);
+
+/* Allocation of expressions.  */
+
+static struct expression *
+new_exp (int nargs, enum expression_operator op,
+	 struct expression * const *args)
+{
+  int i;
+  struct expression *newp;
+
+  /* If any of the argument could not be malloc'ed, just return NULL.  */
+  for (i = nargs - 1; i >= 0; i--)
+    if (args[i] == NULL)
+      goto fail;
+
+  /* Allocate a new expression.  */
+  newp = (struct expression *) malloc (sizeof (*newp));
+  if (newp != NULL)
+    {
+      newp->nargs = nargs;
+      newp->operation = op;
+      for (i = nargs - 1; i >= 0; i--)
+	newp->val.args[i] = args[i];
+      return newp;
+    }
+
+ fail:
+  for (i = nargs - 1; i >= 0; i--)
+    FREE_EXPRESSION (args[i]);
+
+  return NULL;
+}
+
+static inline struct expression *
+new_exp_0 (enum expression_operator op)
+{
+  return new_exp (0, op, NULL);
+}
+
+static inline struct expression *
+new_exp_1 (enum expression_operator op, struct expression *right)
+{
+  struct expression *args[1];
+
+  args[0] = right;
+  return new_exp (1, op, args);
+}
+
+static struct expression *
+new_exp_2 (enum expression_operator op, struct expression *left,
+	   struct expression *right)
+{
+  struct expression *args[2];
+
+  args[0] = left;
+  args[1] = right;
+  return new_exp (2, op, args);
+}
+
+static inline struct expression *
+new_exp_3 (enum expression_operator op, struct expression *bexp,
+	   struct expression *tbranch, struct expression *fbranch)
+{
+  struct expression *args[3];
+
+  args[0] = bexp;
+  args[1] = tbranch;
+  args[2] = fbranch;
+  return new_exp (3, op, args);
+}
+
+%}
+
+/* This declares that all operators have the same associativity and the
+   precedence order as in C.  See [Harbison, Steele: C, A Reference Manual].
+   There is no unary minus and no bitwise operators.
+   Operators with the same syntactic behaviour have been merged into a single
+   token, to save space in the array generated by bison.  */
+%right '?'		/*   ?		*/
+%left '|'		/*   ||		*/
+%left '&'		/*   &&		*/
+%left EQUOP2		/*   == !=	*/
+%left CMPOP2		/*   < > <= >=	*/
+%left ADDOP2		/*   + -	*/
+%left MULOP2		/*   * / %	*/
+%right '!'		/*   !		*/
+
+%token <op> EQUOP2 CMPOP2 ADDOP2 MULOP2
+%token <num> NUMBER
+%type <exp> exp
+
+%%
+
+start:	  exp
+	  {
+	    if ($1 == NULL)
+	      YYABORT;
+	    ((struct parse_args *) arg)->res = $1;
+	  }
+	;
+
+exp:	  exp '?' exp ':' exp
+	  {
+	    $$ = new_exp_3 (qmop, $1, $3, $5);
+	  }
+	| exp '|' exp
+	  {
+	    $$ = new_exp_2 (lor, $1, $3);
+	  }
+	| exp '&' exp
+	  {
+	    $$ = new_exp_2 (land, $1, $3);
+	  }
+	| exp EQUOP2 exp
+	  {
+	    $$ = new_exp_2 ($2, $1, $3);
+	  }
+	| exp CMPOP2 exp
+	  {
+	    $$ = new_exp_2 ($2, $1, $3);
+	  }
+	| exp ADDOP2 exp
+	  {
+	    $$ = new_exp_2 ($2, $1, $3);
+	  }
+	| exp MULOP2 exp
+	  {
+	    $$ = new_exp_2 ($2, $1, $3);
+	  }
+	| '!' exp
+	  {
+	    $$ = new_exp_1 (lnot, $2);
+	  }
+	| 'n'
+	  {
+	    $$ = new_exp_0 (var);
+	  }
+	| NUMBER
+	  {
+	    if (($$ = new_exp_0 (num)) != NULL)
+	      $$->val.num = $1;
+	  }
+	| '(' exp ')'
+	  {
+	    $$ = $2;
+	  }
+	;
+
+%%
+
+void
+internal_function
+FREE_EXPRESSION (struct expression *exp)
+{
+  if (exp == NULL)
+    return;
+
+  /* Handle the recursive case.  */
+  switch (exp->nargs)
+    {
+    case 3:
+      FREE_EXPRESSION (exp->val.args[2]);
+      /* FALLTHROUGH */
+    case 2:
+      FREE_EXPRESSION (exp->val.args[1]);
+      /* FALLTHROUGH */
+    case 1:
+      FREE_EXPRESSION (exp->val.args[0]);
+      /* FALLTHROUGH */
+    default:
+      break;
+    }
+
+  free (exp);
+}
+
+
+static int
+yylex (YYSTYPE *lval, const char **pexp)
+{
+  const char *exp = *pexp;
+  int result;
+
+  while (1)
+    {
+      if (exp[0] == '\0')
+	{
+	  *pexp = exp;
+	  return YYEOF;
+	}
+
+      if (exp[0] != ' ' && exp[0] != '\t')
+	break;
+
+      ++exp;
+    }
+
+  result = *exp++;
+  switch (result)
+    {
+    case '0': case '1': case '2': case '3': case '4':
+    case '5': case '6': case '7': case '8': case '9':
+      {
+	unsigned long int n = result - '0';
+	while (exp[0] >= '0' && exp[0] <= '9')
+	  {
+	    n *= 10;
+	    n += exp[0] - '0';
+	    ++exp;
+	  }
+	lval->num = n;
+	result = NUMBER;
+      }
+      break;
+
+    case '=':
+      if (exp[0] == '=')
+	{
+	  ++exp;
+	  lval->op = equal;
+	  result = EQUOP2;
+	}
+      else
+	result = YYERRCODE;
+      break;
+
+    case '!':
+      if (exp[0] == '=')
+	{
+	  ++exp;
+	  lval->op = not_equal;
+	  result = EQUOP2;
+	}
+      break;
+
+    case '&':
+    case '|':
+      if (exp[0] == result)
+	++exp;
+      else
+	result = YYERRCODE;
+      break;
+
+    case '<':
+      if (exp[0] == '=')
+	{
+	  ++exp;
+	  lval->op = less_or_equal;
+	}
+      else
+	lval->op = less_than;
+      result = CMPOP2;
+      break;
+
+    case '>':
+      if (exp[0] == '=')
+	{
+	  ++exp;
+	  lval->op = greater_or_equal;
+	}
+      else
+	lval->op = greater_than;
+      result = CMPOP2;
+      break;
+
+    case '*':
+      lval->op = mult;
+      result = MULOP2;
+      break;
+
+    case '/':
+      lval->op = divide;
+      result = MULOP2;
+      break;
+
+    case '%':
+      lval->op = module;
+      result = MULOP2;
+      break;
+
+    case '+':
+      lval->op = plus;
+      result = ADDOP2;
+      break;
+
+    case '-':
+      lval->op = minus;
+      result = ADDOP2;
+      break;
+
+    case 'n':
+    case '?':
+    case ':':
+    case '(':
+    case ')':
+      /* Nothing, just return the character.  */
+      break;
+
+    case ';':
+    case '\n':
+    case '\0':
+      /* Be safe and let the user call this function again.  */
+      --exp;
+      result = YYEOF;
+      break;
+
+    default:
+      result = YYERRCODE;
+#if YYDEBUG != 0
+      --exp;
+#endif
+      break;
+    }
+
+  *pexp = exp;
+
+  return result;
+}
+
+
+static void
+yyerror (const char *str)
+{
+  /* Do nothing.  We don't print error messages here.  */
+}