perf($parse) use a faster path when the number of path parts is low

Use a faster path when the number of path tokens is low (ie the common case).
This results in a better than 19x improvement in the time spent in $parse and
produces output that is about the same speed in chrome and substantially faster
in firefox.
http://jsperf.com/angularjs-parse-getter/6

Closes #5359

1 files changed, 1 insertions, 0 deletions

diff --git a/test/ng/parseSpec.js b/test/ng/parseSpec.js
index 2147c4b0..5e985f1f 100644
--- a/test/ng/parseSpec.js
+++ b/test/ng/parseSpec.js
@@ -906,6 +906,7 @@ describe('parser', function() {
             expect($parse('a.b')({a: {b: 0}}, {a: {b:1}})).toEqual(1);
             expect($parse('a.b')({a: null}, {a: {b:1}})).toEqual(1);
             expect($parse('a.b')({a: {b: 0}}, {a: null})).toEqual(undefined);
+            expect($parse('a.b.c')({a: null}, {a: {b: {c: 1}}})).toEqual(1);
           }));
         });