FastCgiRequest::path: Get path from `REQUEST_URI`

Use the `REQUEST_URI` param instead of `SCRIPT_NAME` to get the request
path.

Using `SCRIPT_NAME` caused issues with redirects.

If my FastCGI program has the file name `script.fcgi`, and I set up a
redirect from `/script` to `/script.fcgi`, then `path()` should return
`/script` when using that path.

In the above case, because we were using the `SCRIPT_NAME` param,
`path()` would return `/script.fcgi` instead.

This caused routes defined with a `RouteBuilder` to not match correctly.

Now that we're using `REQUEST_URI`, we need to trim the query string and
hash, which are included in the param value, since we only want the URI
path.

1 files changed, 8 insertions, 4 deletions

diff --git a/src/request.rs b/src/request.rs
index 02f416e..c62002c 100644
--- a/src/request.rs
+++ b/src/request.rs
@@ -189,10 +189,14 @@ impl<'a> FastCgiRequest<'a> {
     /// Returns `/path` when the URI is `http://localhost:8000/path?s=query`.
     /// When the path is empty, returns `/`.
     fn path(request: &fastcgi::Request) -> String {
-        match request.param("SCRIPT_NAME") {
-            Some(p) => p,
-            None => "/".to_owned(),
-        }
+        request.param("REQUEST_URI")
+            .as_ref()
+
+            // Remove query string
+            .map(|uri| uri.split('?').next())
+            .flatten()
+            .unwrap_or("/")
+            .to_owned()
     }
 
     /// Get the URI query string.