Purchaser::generate_secret(): Use a larger random number pool

The `random()` function I was using will sample a value from "the full
representable range"
(https://docs.rs/rand/0.5.5/rand/#the-two-step-process-to-get-a-random-value).

We should really be using longer numbers, so set the sample range to
integers above and including 1 billion.

1 files changed, 4 insertions, 1 deletions

diff --git a/license-generator/src/lib.rs b/license-generator/src/lib.rs
index cc39cdb..df1613e 100644
--- a/license-generator/src/lib.rs
+++ b/license-generator/src/lib.rs
@@ -14,6 +14,8 @@ mod errors {
     }
 }
 
+use rand::Rng;
+
 use errors::*;
 
 struct Purchaser<'a> {
@@ -37,7 +39,8 @@ impl<'a> Purchaser<'a> {
     }
 
     fn generate_secret(&mut self) {
-        let random: usize = rand::random();
+        let mut rng = rand::thread_rng();
+        let random: usize = rng.gen_range(1_000_000_000, std::usize::MAX);
 
         let source = format!("{}{}{}", self.name, self.email, random);
         let digest = sha1::Sha1::from(source).hexdigest();