From d5e9f38f3de317a74f2711e93c7a5df0c89099c7 Mon Sep 17 00:00:00 2001
From: Misko Hevery
Date: Fri, 5 Nov 2010 16:41:36 -0700
Subject: fix error in json parser which did not allow 1.2E10 as number

---
 src/parser.js | 10 +++++-----
 1 file changed, 5 insertions(+), 5 deletions(-)

(limited to 'src/parser.js')

diff --git a/src/parser.js b/src/parser.js
index 8dc8f9c2..77800209 100644
--- a/src/parser.js
+++ b/src/parser.js
@@ -101,26 +101,26 @@ function lex(text, parseStringsForObjects){
            '_' == ch || ch == '$';
   }
   function isExpOperator(ch) {
-    return ch == '-' || ch == '+';
+    return ch == '-' || ch == '+' || isNumber(ch);
   }
   function readNumber() {
     var number = "";
     var start = index;
     while (index < text.length) {
-      var ch = text.charAt(index);
+      var ch = lowercase(text.charAt(index));
       if (ch == '.' || isNumber(ch)) {
         number += ch;
       } else {
         var peekCh = peek();
-        if (ch == 'E' && isExpOperator(peekCh)) {
+        if (ch == 'e' && isExpOperator(peekCh)) {
           number += ch;
         } else if (isExpOperator(ch) &&
             peekCh && isNumber(peekCh) &&
-            number.charAt(number.length - 1) == 'E') {
+            number.charAt(number.length - 1) == 'e') {
           number += ch;
         } else if (isExpOperator(ch) &&
             (!peekCh || !isNumber(peekCh)) &&
-            number.charAt(number.length - 1) == 'E') {
+            number.charAt(number.length - 1) == 'e') {
           throw 'Lexer found invalid exponential value "' + text + '"';
         } else {
           break;
-- 
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